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Joe Bfstplk
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 Posted: Wed Jul 30, 2003 9:28 pm Post subject: ISDN Question |
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Joe Bfstplk
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| Posted: Wed Jul 30, 2003 9:28 pm Post subject: Re: ISDN Question |
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Everybody's explanation is muddled and confuses me worse than I was before.
I have been refering to the chart at Routergod...I hope these guys are
right.
http://routergod.com/ccnabootcamp/isdn_reference_points.html
Its a shame R. Lee Ermy can't set me straight on everything else.
"ArchonOSX" <noone@nowhere.com> wrote in message
news:270720031054343733%noone@nowhere.com...
| Quote: | Okay I am studying for the 607 exam and in two of the books I have it
describes the following:
Chiarella - CCNA self study guide says:
S represents the connection between the TE1 or the TA and the NT-2.
Lammle - CCNA study guide says:
S The reference point between the customer router and an NT2
Lammle goes on to say:
NT2 is typically a provider's equipment, such as a switch or PBX. It
also provides Data Link and Network layer implementation. It's very
rare at customer's premises.
Now they both say that:
U defines the point between the NT1 devices and line-termination
equipment in a carrier network.
Figure 7.2 in Chiarella shows a router with built in NT1 and the
Service Provider's Toll Network connected together at point U.
So here is my question:
If R is the router with BRI and NT1 is connected directly to the
service provider's network at point U, and is located at the customer's
premises, how can the NT2 equipment be located elsewhere and yet be
between points R and U? This sounds very inconvenient. Or does Lammle
simply mean that it is a rarely put between points R and U and the
customer doesn't usually have a setup like this?
Any help appreciated and thanks to all.
--
"Mmmmmmmm Cerveza"
Archon<OSX |
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ArchonOSX
Guest
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| Posted: Tue Aug 05, 2003 2:09 am Post subject: Re: ISDN Question |
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Sorry, I posted that question with the same subject as yours and it got
mixed into your thread. Your thread didn't show on the server I posted
on but showed on a different one that I checked later. It was then I
realized the integration had occured.
Seth Brundle was just as surprised. (check the imdb for the answer)
Archon<OSX>
In article <MmSVa.20963$YN5.19691@sccrnsc01>, Joe Bfstplk
<bfstplk@insightbb.com> wrote:
| Quote: | Everybody's explanation is muddled and confuses me worse than I was before.
I have been refering to the chart at Routergod...I hope these guys are
right.
http://routergod.com/ccnabootcamp/isdn_reference_points.html
Its a shame R. Lee Ermy can't set me straight on everything else.
"ArchonOSX" <noone@nowhere.com> wrote in message
news:270720031054343733%noone@nowhere.com...
Okay I am studying for the 607 exam and in two of the books I have it
describes the following:
Chiarella - CCNA self study guide says:
S represents the connection between the TE1 or the TA and the NT-2.
Lammle - CCNA study guide says:
S The reference point between the customer router and an NT2
Lammle goes on to say:
NT2 is typically a provider's equipment, such as a switch or PBX. It
also provides Data Link and Network layer implementation. It's very
rare at customer's premises.
Now they both say that:
U defines the point between the NT1 devices and line-termination
equipment in a carrier network.
Figure 7.2 in Chiarella shows a router with built in NT1 and the
Service Provider's Toll Network connected together at point U.
So here is my question:
If R is the router with BRI and NT1 is connected directly to the
service provider's network at point U, and is located at the customer's
premises, how can the NT2 equipment be located elsewhere and yet be
between points R and U? This sounds very inconvenient. Or does Lammle
simply mean that it is a rarely put between points R and U and the
customer doesn't usually have a setup like this?
Any help appreciated and thanks to all.
--
"Mmmmmmmm Cerveza"
Archon<OSX
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FireSword
Guest
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| Posted: Thu Aug 28, 2003 7:00 am Post subject: Re: ISDN Question |
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A NT2 is a Layer 2 device, and it can be at the customer premises, but not
likely on the US. In europe you don't need NT1's because the local loop is
already an S/T reference point, more likely to be T because the telco uses
NT2 devices to concentrate different customers connections.
In other words, NO, you can't have a NT2 before a U reference point.
"ArchonOSX" <noone@nowhere.com> wrote in message
news:270720031054343733%noone@nowhere.com...
| Quote: | Okay I am studying for the 607 exam and in two of the books I have it
describes the following:
Chiarella - CCNA self study guide says:
S represents the connection between the TE1 or the TA and the NT-2.
Lammle - CCNA study guide says:
S The reference point between the customer router and an NT2
Lammle goes on to say:
NT2 is typically a provider's equipment, such as a switch or PBX. It
also provides Data Link and Network layer implementation. It's very
rare at customer's premises.
Now they both say that:
U defines the point between the NT1 devices and line-termination
equipment in a carrier network.
Figure 7.2 in Chiarella shows a router with built in NT1 and the
Service Provider's Toll Network connected together at point U.
So here is my question:
If R is the router with BRI and NT1 is connected directly to the
service provider's network at point U, and is located at the customer's
premises, how can the NT2 equipment be located elsewhere and yet be
between points R and U? This sounds very inconvenient. Or does Lammle
simply mean that it is a rarely put between points R and U and the
customer doesn't usually have a setup like this?
Any help appreciated and thanks to all.
--
"Mmmmmmmm Cerveza"
Archon<OSX |
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