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70-293 question: correct subnetting formula

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M D Guest	Posted: Mon Sep 25, 2006 3:08 am    Post subject: 70-293 question: correct subnetting formula Hi everybody! I'm preparing 70-293 on MS press Self Paced training Kit first version. At Chapter 2 it says that to find out how many sbunetted networks are available you just need to calculate 2^y-2 (where y is the n° of the subnetted bits). My question is: isn't this obsolete? From what I studied in 70-291 it's since mid 90's that this rule as been overcome by the 2^y! Any help? Thanks a lot! MD
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LRM Guest	Posted: Mon Sep 25, 2006 5:40 am    Post subject: Re: 70-293 question: correct subnetting formula "M D" <mdbl@NOSPAMinwind.it> wrote in message news:O1IE%23XC4GHA.2420@TK2MSFTNGP02.phx.gbl... Quote: Hi everybody! I'm preparing 70-293 on MS press Self Paced training Kit first version. At Chapter 2 it says that to find out how many sbunetted networks are available you just need to calculate 2^y-2 (where y is the n° of the subnetted bits). My question is: isn't this obsolete? From what I studied in 70-291 it's since mid 90's that this rule as been overcome by the 2^y! Any help? Thanks a lot! MD Not in a subnet. In subnetworks, however, it is likely but not always the case. There is still the one off old device that will require that you remove them. In a subnet you will still need to remove the network and broadcast bit in order to determine the number of usable addresses. -- LRM MCNGP 7^2 www.mcngp.com home of the bogosity singularity.
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