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leeloo.au@gmail.com Guest
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Posted: Wed Jun 27, 2007 12:24 pm Post subject: please help me with this question |
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11. Which of the following IP addresses fall into the CIDR block of
110.68.4.0/18? (Choose three.)
A. 110.68.8.32
B. 110.68.7.64
C. 110.67.6.255
D. 110.66.3.254
E. 110.65.5.128
F. 110.64.12.128
The answer given is as following, but I don't think they are right. In
my opinion, there are two right options A&B
B, C, E. A Class A network address with a /18 is 255.255.192.0. The
subnets in the third octet
are 0, 64, 128, 192. The network address in the question is
110.64.0.0, with a broadcast of
110.64.127.255, since the next subnet is 110.64.128.0. Answers B, C,
and E are correct host IDs. |
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leeloo.au@gmail.com Guest
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Posted: Wed Jun 27, 2007 12:24 pm Post subject: Re: please help me with this question |
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18. You have a network with a subnet of 172.16.17.0/22. Which are
valid host addresses?
A. 172.16.17.1 255.255.255.252
B. 172.16.0.1 255.255.240.0
C. 172.16.20.1 255.255.254.0
D. 172.16.16.1 255.255.255.240
E. 172.16.18.255 255.255.252.0
F. 172.16.0.1 255.255.255.0
The given answer is E only,but I think A is right too.
A Class B network ID with a /22 mask is 255.255.252.0, with a block
size of 4 in the third
octet. The network address in the question is in subnet 172.16.16.0
with a broadcast
address of 172.16.19.255. |
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Capt. Barbossa Guest
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Posted: Wed Jun 27, 2007 8:31 pm Post subject: Re: please help me with this question |
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I am not sure where they got their answers for this. However I'm going
to agree with everybody else and say A and B are the only valid answers.
IP Address: 110.68.4.0
Network Address: 110.68.0.0
Broadcast Address: 110.68.63.255
I checked my subnet math against a subnet calculator and came up with
the same answer you guys did.
leeloo.au@gmail.com wrote:
| Quote: | 11. Which of the following IP addresses fall into the CIDR block of
110.68.4.0/18? (Choose three.)
A. 110.68.8.32
B. 110.68.7.64
C. 110.67.6.255
D. 110.66.3.254
E. 110.65.5.128
F. 110.64.12.128
The answer given is as following, but I don't think they are right. In
my opinion, there are two right options A&B
B, C, E. A Class A network address with a /18 is 255.255.192.0. The
subnets in the third octet
are 0, 64, 128, 192. The network address in the question is
110.64.0.0, with a broadcast of
110.64.127.255, since the next subnet is 110.64.128.0. Answers B, C,
and E are correct host IDs.
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Robert Williams [CertGuar Guest
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Posted: Wed Jun 27, 2007 11:49 pm Post subject: Re: please help me with this question |
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I'm not sure where you got the information, but you may want to see if the
website you got the study material from is in our database.
http://www.CertGuard.com/Search.asp
If you're using testkings or anything of the sorts, you're risking your
certifications.
--
Here are some useful links:
Home: http://www.CertGuard.com
Forums: http://www.CertGuard.com/forums/
Articles: http://www.CertGuard.com/articles.asp
Braindumps: http://www.CertGuard.com/braindumps.asp
Practice Test Providers: http://www.CertGuard.com/reviews.asp
CertSearch http://www.CertGuard.com/search.asp
Study Materials and Books: http://www.CertGuard.com/store.asp
Vendor Links and Emails: http://www.CertGuard.com/links.asp
CertGear: http://www.cafepress.com/certguard
--
CertGuard
<leeloo.au@gmail.com> wrote in message
news:1182937596.835559.192890@e16g2000pri.googlegroups.com...
| Quote: | 11. Which of the following IP addresses fall into the CIDR block of
110.68.4.0/18? (Choose three.)
A. 110.68.8.32
B. 110.68.7.64
C. 110.67.6.255
D. 110.66.3.254
E. 110.65.5.128
F. 110.64.12.128
The answer given is as following, but I don't think they are right. In
my opinion, there are two right options A&B
B, C, E. A Class A network address with a /18 is 255.255.192.0. The
subnets in the third octet
are 0, 64, 128, 192. The network address in the question is
110.64.0.0, with a broadcast of
110.64.127.255, since the next subnet is 110.64.128.0. Answers B, C,
and E are correct host IDs.
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leeloo.au@gmail.com Guest
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Posted: Thu Jun 28, 2007 11:53 am Post subject: Re: please help me with this question |
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On Jun 28, 2:31 am, "Capt. Barbossa" <jasonfr...@hotmail.com> wrote:
| Quote: | I am not sure where they got their answers for this. However I'm going
to agree with everybody else and say A and B are the only valid answers.
IP Address: 110.68.4.0
Network Address: 110.68.0.0
Broadcast Address: 110.68.63.255
I checked my subnet math against a subnet calculator and came up with
the same answer you guys did.
leeloo...@gmail.com wrote:
11. Which of the following IP addresses fall into the CIDR block of
110.68.4.0/18? (Choose three.)
A. 110.68.8.32
B. 110.68.7.64
C. 110.67.6.255
D. 110.66.3.254
E. 110.65.5.128
F. 110.64.12.128
The answer given is as following, but I don't think they are right. In
my opinion, there are two right options A&B
B, C, E. A Class A network address with a /18 is 255.255.192.0. The
subnets in the third octet
are 0, 64, 128, 192. The network address in the question is
110.64.0.0, with a broadcast of
110.64.127.255, since the next subnet is 110.64.128.0. Answers B, C,
and E are correct host IDs.
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thanks, |
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