please help me with this question
 




IT Certification FAQ

 
|
Home
|
Microsoft
|
CISCO
|
CompTIA
|
Exam/Study FAQ
|
Employment FAQ
| Links  | Forums  |
Book Reviews


FAQFAQ  SearchSearch  MemberlistMemberlist  UsergroupsUsergroups  RegisterRegister  ProfileProfile  Log in to check your private messagesPrivate messages  Log inLog in

please help me with this question

 
Post new topic   Reply to topic    Forum Index -> alt.certification.cisco
Author Message
leeloo.au@gmail.com
Guest





PostPosted: Wed Jun 27, 2007 12:24 pm    Post subject: please help me with this question Reply with quote

11. Which of the following IP addresses fall into the CIDR block of
110.68.4.0/18? (Choose three.)
A. 110.68.8.32
B. 110.68.7.64
C. 110.67.6.255
D. 110.66.3.254
E. 110.65.5.128
F. 110.64.12.128


The answer given is as following, but I don't think they are right. In
my opinion, there are two right options A&B

B, C, E. A Class A network address with a /18 is 255.255.192.0. The
subnets in the third octet
are 0, 64, 128, 192. The network address in the question is
110.64.0.0, with a broadcast of
110.64.127.255, since the next subnet is 110.64.128.0. Answers B, C,
and E are correct host IDs.
Back to top
leeloo.au@gmail.com
Guest





PostPosted: Wed Jun 27, 2007 12:24 pm    Post subject: Re: please help me with this question Reply with quote

18. You have a network with a subnet of 172.16.17.0/22. Which are
valid host addresses?
A. 172.16.17.1 255.255.255.252
B. 172.16.0.1 255.255.240.0
C. 172.16.20.1 255.255.254.0
D. 172.16.16.1 255.255.255.240
E. 172.16.18.255 255.255.252.0
F. 172.16.0.1 255.255.255.0

The given answer is E only,but I think A is right too.

A Class B network ID with a /22 mask is 255.255.252.0, with a block
size of 4 in the third
octet. The network address in the question is in subnet 172.16.16.0
with a broadcast
address of 172.16.19.255.
Back to top
Capt. Barbossa
Guest





PostPosted: Wed Jun 27, 2007 8:31 pm    Post subject: Re: please help me with this question Reply with quote

I am not sure where they got their answers for this. However I'm going
to agree with everybody else and say A and B are the only valid answers.

IP Address: 110.68.4.0
Network Address: 110.68.0.0
Broadcast Address: 110.68.63.255

I checked my subnet math against a subnet calculator and came up with
the same answer you guys did.

leeloo.au@gmail.com wrote:
Quote:
11. Which of the following IP addresses fall into the CIDR block of
110.68.4.0/18? (Choose three.)
A. 110.68.8.32
B. 110.68.7.64
C. 110.67.6.255
D. 110.66.3.254
E. 110.65.5.128
F. 110.64.12.128


The answer given is as following, but I don't think they are right. In
my opinion, there are two right options A&B

B, C, E. A Class A network address with a /18 is 255.255.192.0. The
subnets in the third octet
are 0, 64, 128, 192. The network address in the question is
110.64.0.0, with a broadcast of
110.64.127.255, since the next subnet is 110.64.128.0. Answers B, C,
and E are correct host IDs.
Back to top
Robert Williams [CertGuar
Guest





PostPosted: Wed Jun 27, 2007 11:49 pm    Post subject: Re: please help me with this question Reply with quote

I'm not sure where you got the information, but you may want to see if the
website you got the study material from is in our database.

http://www.CertGuard.com/Search.asp

If you're using testkings or anything of the sorts, you're risking your
certifications.


--
Here are some useful links:

Home: http://www.CertGuard.com
Forums: http://www.CertGuard.com/forums/
Articles: http://www.CertGuard.com/articles.asp
Braindumps: http://www.CertGuard.com/braindumps.asp
Practice Test Providers: http://www.CertGuard.com/reviews.asp
CertSearch http://www.CertGuard.com/search.asp
Study Materials and Books: http://www.CertGuard.com/store.asp
Vendor Links and Emails: http://www.CertGuard.com/links.asp
CertGear: http://www.cafepress.com/certguard


--
CertGuard



<leeloo.au@gmail.com> wrote in message
news:1182937596.835559.192890@e16g2000pri.googlegroups.com...
Quote:
11. Which of the following IP addresses fall into the CIDR block of
110.68.4.0/18? (Choose three.)
A. 110.68.8.32
B. 110.68.7.64
C. 110.67.6.255
D. 110.66.3.254
E. 110.65.5.128
F. 110.64.12.128


The answer given is as following, but I don't think they are right. In
my opinion, there are two right options A&B

B, C, E. A Class A network address with a /18 is 255.255.192.0. The
subnets in the third octet
are 0, 64, 128, 192. The network address in the question is
110.64.0.0, with a broadcast of
110.64.127.255, since the next subnet is 110.64.128.0. Answers B, C,
and E are correct host IDs.
Back to top
leeloo.au@gmail.com
Guest





PostPosted: Thu Jun 28, 2007 11:53 am    Post subject: Re: please help me with this question Reply with quote

On Jun 28, 2:31 am, "Capt. Barbossa" <jasonfr...@hotmail.com> wrote:
Quote:
I am not sure where they got their answers for this. However I'm going
to agree with everybody else and say A and B are the only valid answers.

IP Address: 110.68.4.0
Network Address: 110.68.0.0
Broadcast Address: 110.68.63.255

I checked my subnet math against a subnet calculator and came up with
the same answer you guys did.

leeloo...@gmail.com wrote:
11. Which of the following IP addresses fall into the CIDR block of
110.68.4.0/18? (Choose three.)
A. 110.68.8.32
B. 110.68.7.64
C. 110.67.6.255
D. 110.66.3.254
E. 110.65.5.128
F. 110.64.12.128

The answer given is as following, but I don't think they are right. In
my opinion, there are two right options A&B

B, C, E. A Class A network address with a /18 is 255.255.192.0. The
subnets in the third octet
are 0, 64, 128, 192. The network address in the question is
110.64.0.0, with a broadcast of
110.64.127.255, since the next subnet is 110.64.128.0. Answers B, C,
and E are correct host IDs.

thanks,
Back to top
Display posts from previous:   
Post new topic   Reply to topic    Forum Index -> alt.certification.cisco All times are GMT
Page 1 of 1

 

Copyright © 2002-2006 Web-S-Sense Pty. Ltd. All rights reserved.

Powered by phpBB
Advertising | Policies/Disclaimers | Contact us | Link to us


Featured Sites: Free Antivirus and Antispyware Info | Free PC Support | MCSE Directory